
它们都是线程之间进行协作的手段,都属于 Object 对象的方法。必须获得此对象的锁,才能调用这几个方法
package WaNo;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo2")public class demo2 { static final Object lock = new Object(); public static void main(String[] args) throws InterruptedException { new Thread(() -> { synchronized (lock){ log.debug("执行"); try { lock.wait(); } catch (InterruptedException e) { e.printStackTrace(); } log.debug("其他代码"); } },"t1").start(); new Thread(() -> { synchronized (lock){ log.debug("执行"); try { lock.wait(); } catch (InterruptedException e) { e.printStackTrace(); } log.debug("其他代码"); } },"t2").start(); Thread.sleep(2000); log.debug("唤醒 lock 上其他线程"); synchronized (lock){ lock.notify(); //唤醒 lock 上的一个线程(随机) //lock.notifyAll(); //唤醒 lock 上的所有线程 } }}notify()
20:20:58 [t1] c.demo2 - 执行20:20:58 [t2] c.demo2 - 执行20:21:00 [main] c.demo2 - 唤醒 lock 上其他线程20:21:00 [t1] c.demo2 - 其他代码notifyAll()
20:22:04 [t1] c.demo2 - 执行20:22:04 [t2] c.demo2 - 执行20:22:06 [main] c.demo2 - 唤醒 lock 上其他线程20:22:06 [t2] c.demo2 - 其他代码20:22:06 [t1] c.demo2 - 其他代码wait() 方法会释放对象的锁,进入 WaitSet 等待区,从而让其他线程就机会获取对象的锁。无限制等待,直到notify 为止
wait(long n) 有时限的等待, 到 n 毫秒后结束等待,或是被 notify
思考下面的解决方案好不好,为什么?
package WaNo;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo4")public class demo4 { static final Object room = new Object(); static boolean hasCigarette = false; static boolean hasTakeOut = false; public static void main(String[] args) throws InterruptedException { new Thread(() -> { synchronized (room){ log.debug("有烟没?[{}]",hasCigarette); if(!hasCigarette){ log.debug("没烟,睡会!"); try { Thread.sleep(2000); } catch (InterruptedException e) { e.printStackTrace(); } } log.debug("有烟没?[{}]",hasCigarette); if(hasCigarette){ log.debug("开始干活!"); } } },"小南").start(); for(int i=0;i<5;i++){ new Thread(() -> { synchronized (room){ log.debug("开始干活!"); } },"其他人").start(); } Thread.sleep(1000); new Thread(() -> { hasCigarette = true; log.debug("烟到了!"); },"送烟的").start(); }}输出:
20:41:09 [小南] c.demo4 - 有烟没?[false]20:41:09 [小南] c.demo4 - 没烟,睡会!20:41:10 [送烟的] c.demo4 - 烟到了!20:41:11 [小南] c.demo4 - 有烟没?[true]20:41:11 [小南] c.demo4 - 开始干活!20:41:11 [其他人] c.demo4 - 开始干活!20:41:11 [其他人] c.demo4 - 开始干活!20:41:11 [其他人] c.demo4 - 开始干活!20:41:11 [其他人] c.demo4 - 开始干活!20:41:11 [其他人] c.demo4 - 开始干活!思考下面的实现行吗,为什么?
package WaNo.step;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo4")public class step2 { static final Object room = new Object(); static boolean hasCigarette = false; static boolean hasTakeOut = false; public static void main(String[] args) throws InterruptedException { new Thread(() -> { synchronized (room){ log.debug("有烟没?[{}]",hasCigarette); if(!hasCigarette){ log.debug("没烟,睡会!"); try { room.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } log.debug("有烟没?[{}]",hasCigarette); if(hasCigarette){ log.debug("开始干活!"); } } },"小南").start(); for(int i=0;i<5;i++){ new Thread(() -> { synchronized (room){ log.debug("开始干活!"); } },"其他人").start(); } Thread.sleep(1000); new Thread(() -> { synchronized (room){ hasCigarette = true; log.debug("烟到了!"); room.notify(); } },"送烟的").start(); }}输出:
20:46:32 [小南] c.demo4 - 有烟没?[false]20:46:32 [小南] c.demo4 - 没烟,睡会!20:46:32 [其他人] c.demo4 - 开始干活!20:46:32 [其他人] c.demo4 - 开始干活!20:46:32 [其他人] c.demo4 - 开始干活!20:46:32 [其他人] c.demo4 - 开始干活!20:46:32 [其他人] c.demo4 - 开始干活!20:46:33 [送烟的] c.demo4 - 烟到了!20:46:33 [小南] c.demo4 - 有烟没?[true]20:46:33 [小南] c.demo4 - 开始干活!package WaNo.step;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo4")public class step3 { static final Object room = new Object(); static boolean hasCigarette = false; static boolean hasTakeOut = false; public static void main(String[] args) throws InterruptedException { new Thread(() -> { synchronized (room){ log.debug("有烟没?[{}]",hasCigarette); if(!hasCigarette){ log.debug("没烟,睡会!"); try { room.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } log.debug("有烟没?[{}]",hasCigarette); if(hasCigarette){ log.debug("开始干活!"); } else { log.debug("没干成活..."); } } },"小南").start(); new Thread(() -> { synchronized (room) { Thread thread = Thread.currentThread(); log.debug("外卖送到没?[{}]", hasTakeOut); if (!hasTakeOut) { log.debug("没外卖,先歇会!"); try { room.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } log.debug("外卖送到没?[{}]", hasTakeOut); if (hasTakeOut) { log.debug("可以开始干活了"); } else { log.debug("没干成活..."); } } }, "小女").start(); for(int i=0;i<5;i++){ new Thread(() -> { synchronized (room){ log.debug("开始干活!"); } },"其他人").start(); } Thread.sleep(1000); new Thread(() -> { synchronized (room){ hasCigarette = true; log.debug("烟到了!"); room.notify(); } },"送烟的").start(); }}输出:
20:53:12.173 [小南] c.TestCorrectPosture - 有烟没?[false] 20:53:12.176 [小南] c.TestCorrectPosture - 没烟,先歇会!20:53:12.176 [小女] c.TestCorrectPosture - 外卖送到没?[false] 20:53:12.176 [小女] c.TestCorrectPosture - 没外卖,先歇会!20:53:13.174 [送外卖的] c.TestCorrectPosture - 外卖到了噢!20:53:13.174 [小南] c.TestCorrectPosture - 有烟没?[false] 20:53:13.174 [小南] c.TestCorrectPosture - 没干成活...notify 只能随机唤醒一个 WaitSet 中的线程,这时如果有其它线程也在等待,那么就可能唤醒不了正确的线程,称之为【虚假唤醒】
解决方法,改为 notifyAll
new Thread(() -> { synchronized (room) { hasTakeout = true; log.debug("外卖到了噢!"); room.notifyAll(); }}, "送外卖的").start();输出:
20:55:23.978 [小南] c.TestCorrectPosture - 有烟没?[false] 20:55:23.982 [小南] c.TestCorrectPosture - 没烟,先歇会!20:55:23.982 [小女] c.TestCorrectPosture - 外卖送到没?[false] 20:55:23.982 [小女] c.TestCorrectPosture - 没外卖,先歇会!20:55:24.979 [送外卖的] c.TestCorrectPosture - 外卖到了噢!20:55:24.979 [小女] c.TestCorrectPosture - 外卖送到没?[true] 20:55:24.980 [小女] c.TestCorrectPosture - 可以开始干活了20:55:24.980 [小南] c.TestCorrectPosture - 有烟没?[false] 20:55:24.980 [小南] c.TestCorrectPosture - 没干成活...用 notifyAll 仅解决某个线程的唤醒问题,但使用 if + wait 判断仅有一次机会,一旦条件不成立,就没有重新判断的机会了
解决方法,用 while + wait,当条件不成立,再次 wait
将 if 改为 while
while (!hasCigarette) { log.debug("没烟,先歇会!"); try { room.wait(); } catch (InterruptedException e) { e.printStackTrace(); }}输出:
20:58:34.322 [小南] c.TestCorrectPosture - 有烟没?[false] 20:58:34.326 [小南] c.TestCorrectPosture - 没烟,先歇会!20:58:34.326 [小女] c.TestCorrectPosture - 外卖送到没?[false] 20:58:34.326 [小女] c.TestCorrectPosture - 没外卖,先歇会!20:58:35.323 [送外卖的] c.TestCorrectPosture - 外卖到了噢!20:58:35.324 [小女] c.TestCorrectPosture - 外卖送到没?[true] 20:58:35.324 [小女] c.TestCorrectPosture - 可以开始干活了20:58:35.324 [小南] c.TestCorrectPosture - 没烟,先歇会!synchronized(lock) { while(条件不成立) { lock.wait(); } // 干活}//另一个线程synchronized(lock) { lock.notifyAll();}即 Guarded Suspension,用在一个线程等待另一个线程的执行结果
要点

package WaNo.step;import lombok.extern.slf4j.Slf4j;import java.util.ArrayList;import java.util.List;@Slf4j(topic = "c.demo4")public class demo4 { public static void main(String[] args) { //线程1 等待线程2 的下载结果 GuardedObject guardedObject = new GuardedObject(); new Thread(() -> { List<String> list = (List<String>) guardedObject.get(); log.debug("结果的大小是:{}",list.size()); },"t1").start(); new Thread(() -> { log.debug("执行下载"); try { Thread.sleep(5000); List<String> list = new ArrayList<>(); list.add("1"); guardedObject.complete(list); } catch (InterruptedException e) { e.printStackTrace(); } },"t2").start(); }}class GuardedObject { //结果 private Object response; //获取结果 public Object get() { synchronized (this){ //还没有结果 while (response == null){ try { this.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } return response; } } //产生结果 public void complete(Object response){ synchronized (this){ //给结果成员变量赋值 this.response = response; this.notifyAll(); } }}输出:
16:47:15 [t2] c.demo4 - 执行下载16:47:20 [t1] c.demo4 - 结果的大小是:1要点

package WaNo;import lombok.AllArgsConstructor;import lombok.Setter;import lombok.ToString;import lombok.extern.slf4j.Slf4j;import java.util.LinkedList;@Slf4j(topic = "c.demo5")public class demo5 { public static void main(String[] args) { MessageQueue queue = new MessageQueue(2); for (int i = 0; i < 3; i++) { int id = i; new Thread(() -> { queue.put(new Message(id,"值"+id)); },"生产者" + i).start(); } new Thread(() -> { while (true){ try { Thread.sleep(1000); Message message = queue.take(); } catch (InterruptedException e) { e.printStackTrace(); } } },"消费者").start(); }}//消息队列类(线程间通信)@Slf4j(topic = "c.MessageQueue")class MessageQueue { //消息队列集合 private LinkedList<Message> list = new LinkedList<>(); //队列容量 private int capcity; public MessageQueue(int capcity){ this.capcity = capcity; } //获取消息 public Message take(){ //检查队列是否为空 synchronized (list){ while (list.isEmpty()){ try { log.debug("队列为空,消费者线程等待"); list.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } //从队列头部获取消息返回 Message message = list.removeFirst(); log.debug("已消费消息 {}",message); list.notifyAll(); return message; } } //存入消息 public void put(Message message){ synchronized (list){ //检查队列是否已满 while (list.size() == capcity){ try { log.debug("队列已满,生产者线程等待"); list.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } //将消息加入队列的尾部 list.addLast(message); log.debug("已生产消息 {}",message); list.notifyAll(); } }}@Setter@AllArgsConstructor@ToString@Slf4j(topic = "c.Message")final class Message { private int id; private Object value;}输出:
17:18:49 [生产者0] c.MessageQueue - 已生产消息 Message(id=0, value=值0)17:18:49 [生产者2] c.MessageQueue - 已生产消息 Message(id=2, value=值2)17:18:49 [生产者1] c.MessageQueue - 队列已满,生产者线程等待17:18:50 [消费者] c.MessageQueue - 已消费消息 Message(id=0, value=值0)17:18:50 [生产者1] c.MessageQueue - 已生产消息 Message(id=1, value=值1)17:18:51 [消费者] c.MessageQueue - 已消费消息 Message(id=2, value=值2)17:18:52 [消费者] c.MessageQueue - 已消费消息 Message(id=1, value=值1)17:18:53 [消费者] c.MessageQueue - 队列为空,消费者线程等待它们是 LockSupport 类中的方法
// 暂停当前线程LockSupport.park(); // 恢复某个线程的运行LockSupport.unpark(暂停线程对象)先 park 再 unpark
Thread t1 = new Thread(() -> { log.debug("start..."); sleep(1); log.debug("park..."); LockSupport.park(); log.debug("resume...");},"t1");t1.start();Thread.sleep(2);log.debug("unpark...");LockSupport.unpark(t1);输出:
18:42:52.585 c.TestParkUnpark [t1] - start... 18:42:53.589 c.TestParkUnpark [t1] - park... 18:42:54.583 c.TestParkUnpark [main] - unpark... 18:42:54.583 c.TestParkUnpark [t1] - resume...先 unpark 再 park
Thread t1 = new Thread(() -> { log.debug("start..."); sleep(2); log.debug("park..."); LockSupport.park(); log.debug("resume...");}, "t1");t1.start();sleep(1);log.debug("unpark...");LockSupport.unpark(t1);输出:
18:43:50.765 c.TestParkUnpark [t1] - start... 18:43:51.764 c.TestParkUnpark [main] - unpark... 18:43:52.769 c.TestParkUnpark [t1] - park... 18:43:52.769 c.TestParkUnpark [t1] - resume...与 Object 的 wait & notify 相比
每个线程都有自己的一个 Parker 对象,由三部分组成 _counter , _cond 和 _mutex




假设有线程 Thread t
NEW --> RUNNABLE
当调用 t.start() 方法时,由 NEW --> RUNNABLE
? RUNNABLE <--> WAITING
t 线程用 synchronized(obj) 获取了对象锁后
RUNNABLE <--> WAITING
RUNNABLE <--> WAITING
? RUNNABLE <--> TIMED_WAITING
t 线程用 synchronized(obj) 获取了对象锁后
RUNNABLE <--> TIMED_WAITING
RUNNABLE <--> TIMED_WAITING
RUNNABLE <--> TIMED_WAITING
RUNNABLE <--> BLOCKED
RUNNABLE <--> TERMINATED
当前线程所有代码运行完毕,进入 TERMINATED
package WaNo;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo6")public class demo6 { public static void main(String[] args) { BigRoom bigRoom = new BigRoom(); new Thread(() -> { bigRoom.study(); },"r1").start(); new Thread(() -> { bigRoom.sleep(); },"r2").start(); }}@Slf4j(topic = "c.BigRoom")class BigRoom { private final Object studyRoom = new Object(); private final Object bedRoom = new Object(); public void sleep(){ synchronized (bedRoom){ log.debug("sleep two hours"); try { Thread.sleep(2000); } catch (InterruptedException e) { e.printStackTrace(); } } } public void study(){ synchronized (studyRoom){ log.debug("study one hour"); try { Thread.sleep(1000); } catch (InterruptedException e) { e.printStackTrace(); } } }}输出:
20:01:42 [r2] c.BigRoom - sleep two hours20:01:42 [r1] c.BigRoom - study one hour将锁的粒度细分
有这样的情况:一个线程需要同时获取多把锁,这时就容易发生死锁
t1 线程 获得 A对象 锁,接下来想获取 B对象 的锁 t2 线程 获得 B对象 锁,接下来想获取 A对象 的锁
Object A = new Object();Object B = new Object();Thread t1 = new Thread(() -> { synchronized (A) { log.debug("lock A"); sleep(1); synchronized (B) { log.debug("lock B"); log.debug("操作..."); } }}, "t1");Thread t2 = new Thread(() -> { synchronized (B) { log.debug("lock B"); sleep(0.5); synchronized (A) { log.debug("lock A"); log.debug("操作..."); } }}, "t2");t1.start();t2.start();输出:
12:22:06.962 [t2] c.TestDeadLock - lock B 12:22:06.962 [t1] c.TestDeadLock - lock A
有五位哲学家,围坐在圆桌旁。
这种线程没有按预期结束,执行不下去的情况,归类为【活跃性】问题,除了死锁以外,还有活锁和饥饿者两种情况
活锁出现在两个线程互相改变对方的结束条件,最后谁也无法结束
public class TestLiveLock { static volatile int count = 10; static final Object lock = new Object(); public static void main(String[] args) { new Thread(() -> { // 期望减到 0 退出循环 while (count > 0) { sleep(0.2); count--; log.debug("count: {}", count); } }, "t1").start(); new Thread(() -> { // 期望超过 20 退出循环 while (count < 20) { sleep(0.2); count++; log.debug("count: {}", count); } }, "t2").start(); }一个线程由于优先级太低,始终得不到 CPU 调度执行,也不能够结束
相对于 synchronized 它具备如下特点
与 synchronized 一样,都支持可重入
基本语法
// 获取锁reentrantLock.lock();try { // 临界区} finally { // 释放锁 reentrantLock.unlock();}可重入是指同一个线程如果首次获得了这把锁,那么因为它是这把锁的拥有者,因此有权利再次获取这把锁如果是不可重入锁,那么第二次获得锁时,自己也会被锁挡住
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo1")public class demo1 { private static ReentrantLock lock = new ReentrantLock(); public static void main(String[] args) { lock.lock(); try { log.debug("enter main"); m1(); }finally { lock.unlock(); } } public static void m1(){ lock.lock(); try { log.debug("enter m1"); m2(); }finally { lock.unlock(); } } public static void m2(){ lock.lock(); try { log.debug("enter m2"); }finally { lock.unlock(); } }}输出:
20:19:19 [main] c.demo1 - enter main20:19:19 [main] c.demo1 - enter m120:19:19 [main] c.demo1 - enter m2package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo2")public class demo2 { private static ReentrantLock lock = new ReentrantLock(); public static void main(String[] args) throws InterruptedException { Thread t1 = new Thread(() -> { try { //如果没有竞争,此方法会获取对象的锁 //如果有竞争,就进入阻塞队列,可以被其他线程用 interrupt 打断 log.debug("尝试获得锁"); lock.lockInterruptibly(); } catch (InterruptedException e) { e.printStackTrace(); log.debug("未获得锁,返回"); return; } try { log.debug("获取到锁"); }finally { lock.unlock(); } }, "t1"); lock.lock(); t1.start(); Thread.sleep(1000); log.debug("打断t1"); t1.interrupt(); }}输出:
20:26:05 [t1] c.demo2 - 尝试获得锁20:26:06 [main] c.demo2 - 打断t120:26:06 [t1] c.demo2 - 未获得锁,返回java.lang.InterruptedException at java.util.concurrent.locks.AbstractQueuedSynchronizer.doAcquireInterruptibly(AbstractQueuedSynchronizer.java:898) at java.util.concurrent.locks.AbstractQueuedSynchronizer.acquireInterruptibly(AbstractQueuedSynchronizer.java:1222) at java.util.concurrent.locks.ReentrantLock.lockInterruptibly(ReentrantLock.java:335) at ReentrantLockDemo.demo2.lambda$main$0(demo2.java:16) at java.lang.Thread.run(Thread.java:748)Process finished with exit code 0注意如果是不可中断模式,那么即使使用了 interrupt 也不会让等待中断
立刻失败
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo3")public class demo3 { private static ReentrantLock lock = new ReentrantLock(); public static void main(String[] args) { Thread t1 = new Thread(() -> { log.debug("尝试获得锁"); if(!lock.tryLock()){ log.debug("获取不到锁"); return; } try { log.debug("获得到锁"); }finally { lock.unlock(); } },"t1"); lock.lock(); log.debug("获得到锁"); t1.start(); }}输出:
20:31:15 [main] c.demo3 - 获得到锁20:31:15 [t1] c.demo3 - 尝试获得锁20:31:15 [t1] c.demo3 - 获取不到锁超时失败
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import sun.reflect.generics.tree.Tree;import java.util.concurrent.TimeUnit;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo3")public class demo3 { private static ReentrantLock lock = new ReentrantLock(); public static void main(String[] args) throws InterruptedException { Thread t1 = new Thread(() -> { log.debug("尝试获得锁"); try { if(!lock.tryLock(1, TimeUnit.SECONDS)){ log.debug("获取不到锁"); return; } } catch (InterruptedException e) { e.printStackTrace(); log.debug("获取不到锁"); return; } try { log.debug("获得到锁"); }finally { lock.unlock(); } },"t1"); lock.lock(); log.debug("获得到锁"); Thread.sleep(1000); lock.unlock(); t1.start(); }}输出:
20:34:03 [main] c.demo3 - 获得到锁20:34:04 [t1] c.demo3 - 尝试获得锁20:34:04 [t1] c.demo3 - 获得到锁ReentrantLock 默认是不公平的
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo4")public class demo4 { public static void main(String[] args) { ReentrantLock lock = new ReentrantLock(false); lock.lock(); for (int i = 0; i < 500; i++) { new Thread(() -> { lock.lock(); try { System.out.println(Thread.currentThread().getName() + " running..."); } finally { lock.unlock(); } }, "t" + i).start(); }// 1s 之后去争抢锁 Thread.sleep(1000); new Thread(() -> { System.out.println(Thread.currentThread().getName() + " start..."); lock.lock(); try { System.out.println(Thread.currentThread().getName() + " running..."); } finally { lock.unlock(); } }, "强行插入").start(); lock.unlock(); }}强行插入,有机会在中间输出
注意:该实验不一定总能复现
t39 running... t40 running... t41 running... t42 running... t43 running... 强行插入 start... 强行插入 running... t44 running... t45 running... t46 running... t47 running... t49 running...改为公平锁后
ReentrantLock lock = new ReentrantLock(true);强行插入,总是在最后输出
t465 running... t464 running... t477 running... t442 running... t468 running... t493 running... t482 running... t485 running... t481 running... 强行插入 running...公平锁一般没有必要,会降低并发度
ReentrantLock 的条件变量比 synchronized 强大之处在于,它是支持多个条件变量的,这就好比
使用要点:
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.Condition;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo4")public class demo4 { private static ReentrantLock lock = new ReentrantLock(); public static void main(String[] args) { //创建一个新的条件变量(休息室) Condition condition1 = lock.newCondition(); Condition condition2 = lock.newCondition(); lock.lock(); //进入休息室等待 condition1.await(); condition1.signal(); //condition1.signalAll(); }}比如,必须先 2 后 1 打印
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;@Slf4j(topic = "c.demo4")public class demo4 { static final Object lock = new Object(); //表示 t2 是否被运行过 static boolean t2runned = false; public static void main(String[] args) { Thread t1 = new Thread(() -> { synchronized (lock){ while (!t2runned){ try { lock.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } log.debug("1"); } },"t1"); Thread t2 = new Thread(() -> { synchronized (lock){ log.debug("2"); t2runned = true; lock.notify(); } },"t2"); t1.start(); t2.start(); }}输出:
20:49:28 [t2] c.demo4 - 220:49:28 [t1] c.demo4 - 1可以看到,实现上很麻烦:
可以使用 LockSupport 类的 park 和 unpark 来简化上面的题目:
package ReentrantLockDemo;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.LockSupport;@Slf4j(topic = "demo5")public class demo5 { public static void main(String[] args) { Thread t1 = new Thread(() -> { LockSupport.park(); log.debug("1"); }, "t1"); t1.start(); new Thread(() -> { log.debug("2"); LockSupport.unpark(t1); },"t2").start(); }}线程 1 输出 a 5 次,线程 2 输出 b 5 次,线程 3 输出 c 5 次。现在要求输出 abcabcabcabcabc 怎么实现
package ReentrantLockDemo;import lombok.AllArgsConstructor;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.LockSupport;@Slf4j(topic = "demo5")public class demo5 { public static void main(String[] args) { WaitNotify wn = new WaitNotify(1,5); new Thread(() -> { wn.print("a",1,2); }).start(); new Thread(() -> { wn.print("b",2,3); }).start(); new Thread(() -> { wn.print("c",3,1); }).start(); }}/* 输出内容 等待标记 下一个标记 a 1 2 b 2 3 c 3 1 */@AllArgsConstructorclass WaitNotify{ //等待标记 private int flag; //循环次数 private int loopNumber; //打印 public void print(String str,int waitFlag,int nextFlag){ for (int i = 0; i < loopNumber; i++) { synchronized (this){ while (flag != waitFlag){ try { this.wait(); } catch (InterruptedException e) { e.printStackTrace(); } } System.out.print(str); flag = nextFlag; this.notifyAll(); } } }}输出:
abcabcabcabcabcpackage ReentrantLockDemo;import lombok.AllArgsConstructor;import lombok.extern.slf4j.Slf4j;import java.util.concurrent.locks.Condition;import java.util.concurrent.locks.ReentrantLock;@Slf4j(topic = "c.demo6")public class demo6 { public static void main(String[] args) throws InterruptedException { AwaitSignal awaitSignal = new AwaitSignal(5); Condition a = awaitSignal.newCondition(); Condition b = awaitSignal.newCondition(); Condition c = awaitSignal.newCondition(); new Thread(() -> { awaitSignal.print("a", a, b); }).start(); new Thread(() -> { awaitSignal.print("b", b, c); }).start(); new Thread(() -> { awaitSignal.print("c", c, a); }).start(); Thread.sleep(1000); awaitSignal.lock(); try { System.out.println("开始。。。"); a.signal(); }finally { awaitSignal.unlock(); } }}@AllArgsConstructorclass AwaitSignal extends ReentrantLock { private int loopNumber; /** * @param str 打印内容 * @param current 进入哪一间休息室 * @param next 下一间休息室 */ public void print(String str,Condition current,Condition next){ for (int i = 0; i < loopNumber; i++) { lock(); try { try { current.await(); System.out.print(str); next.signal(); } catch (InterruptedException e) { e.printStackTrace(); } }finally { unlock(); } } }}输出:
开始。。。abcabcabcabcabcpackage ReentrantLockDemo;import lombok.AllArgsConstructor;import java.util.concurrent.locks.LockSupport;public class demo7 { static Thread t1; static Thread t2; static Thread t3; public static void main(String[] args) { ParkUnpark pu = new ParkUnpark(5); t1 = new Thread(() -> { pu.print("a", t2); },"t1"); t2 = new Thread(() -> { pu.print("b", t3); },"t2"); t3 = new Thread(() -> { pu.print("c", t1); },"t3"); t1.start(); t2.start(); t3.start(); LockSupport.unpark(t1); }}@AllArgsConstructorclass ParkUnpark{ private int loopNumber; public void print(String str,Thread next){ for (int i = 0; i < loopNumber; i++) { LockSupport.park(); System.out.print(str); LockSupport.unpark(next); } }}输出:
abcabcabcabcabc